Base | Representation |
---|---|
bin | 111100000011100011… |
… | …0100000000001010011 |
3 | 110022220000100111220212 |
4 | 1320013012200001103 |
5 | 4103111322212121 |
6 | 135125215154335 |
7 | 12213644205263 |
oct | 1700706400123 |
9 | 408800314825 |
10 | 128968163411 |
11 | 4a77119101a |
12 | 20bb32159ab |
13 | c21419b739 |
14 | 63564317a3 |
15 | 354c49425b |
hex | 1e071a0053 |
128968163411 has 2 divisors, whose sum is σ = 128968163412. Its totient is φ = 128968163410.
The previous prime is 128968163383. The next prime is 128968163413. The reversal of 128968163411 is 114361869821.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-128968163411 is a prime.
Together with 128968163413, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 128968163411.
It is not a weakly prime, because it can be changed into another prime (128968163413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64484081705 + 64484081706.
It is an arithmetic number, because the mean of its divisors is an integer number (64484081706).
Almost surely, 2128968163411 is an apocalyptic number.
128968163411 is a deficient number, since it is larger than the sum of its proper divisors (1).
128968163411 is an equidigital number, since it uses as much as digits as its factorization.
128968163411 is an evil number, because the sum of its binary digits is even.
The product of its digits is 497664, while the sum is 50.
The spelling of 128968163411 in words is "one hundred twenty-eight billion, nine hundred sixty-eight million, one hundred sixty-three thousand, four hundred eleven".
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