Base | Representation |
---|---|
bin | 1011101110101100101111… |
… | …1011011100101000011101 |
3 | 1200122221012001110112201001 |
4 | 2323223023323130220131 |
5 | 3142300334233244323 |
6 | 43232432104150301 |
7 | 2500525350164245 |
oct | 273531373345035 |
9 | 50587161415631 |
10 | 12896913181213 |
11 | 41226062a5a96 |
12 | 1543612168391 |
13 | 7272347b74a9 |
14 | 3282dd03cb25 |
15 | 1757294593ad |
hex | bbacbedca1d |
12896913181213 has 2 divisors, whose sum is σ = 12896913181214. Its totient is φ = 12896913181212.
The previous prime is 12896913181183. The next prime is 12896913181241. The reversal of 12896913181213 is 31218131969821.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12618252719524 + 278660461689 = 3552218^2 + 527883^2 .
It is a cyclic number.
It is not a de Polignac number, because 12896913181213 - 217 = 12896913050141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12896913181253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6448456590606 + 6448456590607.
It is an arithmetic number, because the mean of its divisors is an integer number (6448456590607).
Almost surely, 212896913181213 is an apocalyptic number.
It is an amenable number.
12896913181213 is a deficient number, since it is larger than the sum of its proper divisors (1).
12896913181213 is an equidigital number, since it uses as much as digits as its factorization.
12896913181213 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1119744, while the sum is 55.
The spelling of 12896913181213 in words is "twelve trillion, eight hundred ninety-six billion, nine hundred thirteen million, one hundred eighty-one thousand, two hundred thirteen".
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