1289809941213 has 4 divisors (see below), whose sum is σ = 1719746588288. Its totient is φ = 859873294140.

The previous prime is 1289809941181. The next prime is 1289809941239. The reversal of 1289809941213 is 3121499089821.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1289809941213 - 2⁵ = 1289809941181 is a prime.

It is a super-2 number, since 2×1289809941213² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1289809941283) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214968323533 + ... + 214968323538.

It is an arithmetic number, because the mean of its divisors is an integer number (429936647072).

Almost surely, 2^{1289809941213} is an apocalyptic number.

It is an amenable number.

1289809941213 is a deficient number, since it is larger than the sum of its proper divisors (429936647075).

1289809941213 is an equidigital number, since it uses as much as digits as its factorization.

1289809941213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 429936647074.

The product of its (nonzero) digits is 2239488, while the sum is 57.

The spelling of 1289809941213 in words is "one trillion, two hundred eighty-nine billion, eight hundred nine million, nine hundred forty-one thousand, two hundred thirteen".