Base | Representation |
---|---|
bin | 111100000110110111… |
… | …0100000000000111001 |
3 | 110100011202111110201121 |
4 | 1320031232200000321 |
5 | 4103323300444231 |
6 | 135144225345241 |
7 | 12216464024032 |
oct | 1701556400071 |
9 | 410152443647 |
10 | 129079312441 |
11 | 4a8189a7a22 |
12 | 21024498221 |
13 | c231216ab1 |
14 | 63670c5a89 |
15 | 35570ec311 |
hex | 1e0dba0039 |
129079312441 has 2 divisors, whose sum is σ = 129079312442. Its totient is φ = 129079312440.
The previous prime is 129079312429. The next prime is 129079312447. The reversal of 129079312441 is 144213970921.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 127909946025 + 1169366416 = 357645^2 + 34196^2 .
It is a cyclic number.
It is not a de Polignac number, because 129079312441 - 227 = 128945094713 is a prime.
It is a super-2 number, since 2×1290793124412 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (129079312447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64539656220 + 64539656221.
It is an arithmetic number, because the mean of its divisors is an integer number (64539656221).
Almost surely, 2129079312441 is an apocalyptic number.
It is an amenable number.
129079312441 is a deficient number, since it is larger than the sum of its proper divisors (1).
129079312441 is an equidigital number, since it uses as much as digits as its factorization.
129079312441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108864, while the sum is 43.
The spelling of 129079312441 in words is "one hundred twenty-nine billion, seventy-nine million, three hundred twelve thousand, four hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •