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1291161319933 is a prime number
BaseRepresentation
bin10010110010011111001…
…101100011100111111101
311120102201020210222120011
4102302133031203213331
5132123244244214213
62425052404023221
7162166116065002
oct22623715434775
94512636728504
101291161319933
1145863a9a5021
1218a29b391b11
13949a9baa634
14466c77678a9
15238bceb203d
hex12c9f3639fd

1291161319933 has 2 divisors, whose sum is σ = 1291161319934. Its totient is φ = 1291161319932.

The previous prime is 1291161319897. The next prime is 1291161319949. The reversal of 1291161319933 is 3399131611921.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 853105307769 + 438056012164 = 923637^2 + 661858^2 .

It is a cyclic number.

It is not a de Polignac number, because 1291161319933 - 29 = 1291161319421 is a prime.

It is a super-2 number, since 2×12911613199332 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1291161319033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 645580659966 + 645580659967.

It is an arithmetic number, because the mean of its divisors is an integer number (645580659967).

Almost surely, 21291161319933 is an apocalyptic number.

It is an amenable number.

1291161319933 is a deficient number, since it is larger than the sum of its proper divisors (1).

1291161319933 is an equidigital number, since it uses as much as digits as its factorization.

1291161319933 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 236196, while the sum is 49.

The spelling of 1291161319933 in words is "one trillion, two hundred ninety-one billion, one hundred sixty-one million, three hundred nineteen thousand, nine hundred thirty-three".