Base | Representation |
---|---|
bin | 11000000011011000… |
… | …01001110000011111 |
3 | 1020022221120020111201 |
4 | 30001230021300133 |
5 | 202421243102112 |
6 | 5533211500331 |
7 | 635000562055 |
oct | 140154116037 |
9 | 36287506451 |
10 | 12913253407 |
11 | 552721645a |
12 | 26047576a7 |
13 | 12aa41b862 |
14 | 8a70281d5 |
15 | 508a19257 |
hex | 301b09c1f |
12913253407 has 2 divisors, whose sum is σ = 12913253408. Its totient is φ = 12913253406.
The previous prime is 12913253401. The next prime is 12913253467. The reversal of 12913253407 is 70435231921.
It is a weak prime.
It is an emirp because it is prime and its reverse (70435231921) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12913253407 - 23 = 12913253399 is a prime.
It is a super-2 number, since 2×129132534072 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12913253401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6456626703 + 6456626704.
It is an arithmetic number, because the mean of its divisors is an integer number (6456626704).
Almost surely, 212913253407 is an apocalyptic number.
12913253407 is a deficient number, since it is larger than the sum of its proper divisors (1).
12913253407 is an equidigital number, since it uses as much as digits as its factorization.
12913253407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 45360, while the sum is 37.
The spelling of 12913253407 in words is "twelve billion, nine hundred thirteen million, two hundred fifty-three thousand, four hundred seven".
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