Base | Representation |
---|---|
bin | 11000000011011011… |
… | …11001000110100101 |
3 | 1020022222102102010012 |
4 | 30001231321012211 |
5 | 202421402200402 |
6 | 5533225340005 |
7 | 635004501524 |
oct | 140155710645 |
9 | 36288372105 |
10 | 12913709477 |
11 | 55274a8079 |
12 | 2604937605 |
13 | 12aa54b316 |
14 | 8a71064bb |
15 | 508aa9452 |
hex | 301b791a5 |
12913709477 has 2 divisors, whose sum is σ = 12913709478. Its totient is φ = 12913709476.
The previous prime is 12913709449. The next prime is 12913709489. The reversal of 12913709477 is 77490731921.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12880888036 + 32821441 = 113494^2 + 5729^2 .
It is an emirp because it is prime and its reverse (77490731921) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12913709477 - 224 = 12896932261 is a prime.
It is a super-2 number, since 2×129137094772 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12913709437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6456854738 + 6456854739.
It is an arithmetic number, because the mean of its divisors is an integer number (6456854739).
Almost surely, 212913709477 is an apocalyptic number.
It is an amenable number.
12913709477 is a deficient number, since it is larger than the sum of its proper divisors (1).
12913709477 is an equidigital number, since it uses as much as digits as its factorization.
12913709477 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 666792, while the sum is 50.
The spelling of 12913709477 in words is "twelve billion, nine hundred thirteen million, seven hundred nine thousand, four hundred seventy-seven".
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