Base | Representation |
---|---|
bin | 11000000011011110… |
… | …10111100000001001 |
3 | 1020100000011001111221 |
4 | 30001233113200021 |
5 | 202422002034022 |
6 | 5533241522041 |
7 | 635011002025 |
oct | 140157274011 |
9 | 36300131457 |
10 | 12914096137 |
11 | 5527741628 |
12 | 2604aa3321 |
13 | 12aa655307 |
14 | 8a71a7385 |
15 | 508b33cc7 |
hex | 301bd7809 |
12914096137 has 2 divisors, whose sum is σ = 12914096138. Its totient is φ = 12914096136.
The previous prime is 12914096093. The next prime is 12914096161. The reversal of 12914096137 is 73169041921.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12719102841 + 194993296 = 112779^2 + 13964^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12914096137 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12914096093 and 12914096102.
It is not a weakly prime, because it can be changed into another prime (12914096177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6457048068 + 6457048069.
It is an arithmetic number, because the mean of its divisors is an integer number (6457048069).
Almost surely, 212914096137 is an apocalyptic number.
It is an amenable number.
12914096137 is a deficient number, since it is larger than the sum of its proper divisors (1).
12914096137 is an equidigital number, since it uses as much as digits as its factorization.
12914096137 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81648, while the sum is 43.
The spelling of 12914096137 in words is "twelve billion, nine hundred fourteen million, ninety-six thousand, one hundred thirty-seven".
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