Base | Representation |
---|---|
bin | 100001110011101010… |
… | …000000110010000001 |
3 | 10110200211002202000020 |
4 | 201303222000302001 |
5 | 1043320313201312 |
6 | 24402005444053 |
7 | 2423360012022 |
oct | 416352006201 |
9 | 113624082006 |
10 | 36300131457 |
11 | 14438529047 |
12 | 7050a10629 |
13 | 35666a6735 |
14 | 1a85062c49 |
15 | e26c9978c |
hex | 873a80c81 |
36300131457 has 4 divisors (see below), whose sum is σ = 48400175280. Its totient is φ = 24200087636.
The previous prime is 36300131453. The next prime is 36300131471. The reversal of 36300131457 is 75413100363.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 75413100363 = 3 ⋅25137700121.
It is a cyclic number.
It is not a de Polignac number, because 36300131457 - 22 = 36300131453 is a prime.
It is not an unprimeable number, because it can be changed into a prime (36300131453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6050021907 + ... + 6050021912.
It is an arithmetic number, because the mean of its divisors is an integer number (12100043820).
Almost surely, 236300131457 is an apocalyptic number.
It is an amenable number.
36300131457 is a deficient number, since it is larger than the sum of its proper divisors (12100043823).
36300131457 is a wasteful number, since it uses less digits than its factorization.
36300131457 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12100043822.
The product of its (nonzero) digits is 22680, while the sum is 33.
The spelling of 36300131457 in words is "thirty-six billion, three hundred million, one hundred thirty-one thousand, four hundred fifty-seven".
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