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36300131457 = 312100043819
BaseRepresentation
bin100001110011101010…
…000000110010000001
310110200211002202000020
4201303222000302001
51043320313201312
624402005444053
72423360012022
oct416352006201
9113624082006
1036300131457
1114438529047
127050a10629
1335666a6735
141a85062c49
15e26c9978c
hex873a80c81

36300131457 has 4 divisors (see below), whose sum is σ = 48400175280. Its totient is φ = 24200087636.

The previous prime is 36300131453. The next prime is 36300131471. The reversal of 36300131457 is 75413100363.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 75413100363 = 325137700121.

It is a cyclic number.

It is not a de Polignac number, because 36300131457 - 22 = 36300131453 is a prime.

It is not an unprimeable number, because it can be changed into a prime (36300131453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6050021907 + ... + 6050021912.

It is an arithmetic number, because the mean of its divisors is an integer number (12100043820).

Almost surely, 236300131457 is an apocalyptic number.

It is an amenable number.

36300131457 is a deficient number, since it is larger than the sum of its proper divisors (12100043823).

36300131457 is a wasteful number, since it uses less digits than its factorization.

36300131457 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12100043822.

The product of its (nonzero) digits is 22680, while the sum is 33.

The spelling of 36300131457 in words is "thirty-six billion, three hundred million, one hundred thirty-one thousand, four hundred fifty-seven".

Divisors: 1 3 12100043819 36300131457