Base | Representation |
---|---|
bin | 11000000011100010… |
… | …11111000011101011 |
3 | 1020100001012021011011 |
4 | 30001301133003223 |
5 | 202422122320441 |
6 | 5533301444351 |
7 | 635015503546 |
oct | 140161370353 |
9 | 36301167134 |
10 | 12914651371 |
11 | 5527a907a6 |
12 | 26051106b7 |
13 | 12aa7bac5b |
14 | 8a72ad85d |
15 | 508be3581 |
hex | 301c5f0eb |
12914651371 has 4 divisors (see below), whose sum is σ = 12955912552. Its totient is φ = 12873390192.
The previous prime is 12914651369. The next prime is 12914651389. The reversal of 12914651371 is 17315641921.
12914651371 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 17315641921 = 43 ⋅402689347.
It is a cyclic number.
It is not a de Polignac number, because 12914651371 - 21 = 12914651369 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12914651471) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20630121 + ... + 20630746.
It is an arithmetic number, because the mean of its divisors is an integer number (3238978138).
Almost surely, 212914651371 is an apocalyptic number.
12914651371 is a deficient number, since it is larger than the sum of its proper divisors (41261181).
12914651371 is an equidigital number, since it uses as much as digits as its factorization.
12914651371 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 41261180.
The product of its digits is 45360, while the sum is 40.
The spelling of 12914651371 in words is "twelve billion, nine hundred fourteen million, six hundred fifty-one thousand, three hundred seventy-one".
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