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129253000531 is a prime number
BaseRepresentation
bin111100001100000010…
…1000100010101010011
3110100121212022201222211
41320120011010111103
54104202232004111
6135213352212551
712224003243224
oct1703005042523
9410555281884
10129253000531
114a8a7a493a6
122107269a157
13c25b1baa05
1463821b924b
1535674aa521
hex1e18144553

129253000531 has 2 divisors, whose sum is σ = 129253000532. Its totient is φ = 129253000530.

The previous prime is 129253000523. The next prime is 129253000537. The reversal of 129253000531 is 135000352921.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 129253000531 - 23 = 129253000523 is a prime.

It is a super-2 number, since 2×1292530005312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 129253000493 and 129253000502.

It is not a weakly prime, because it can be changed into another prime (129253000537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64626500265 + 64626500266.

It is an arithmetic number, because the mean of its divisors is an integer number (64626500266).

Almost surely, 2129253000531 is an apocalyptic number.

129253000531 is a deficient number, since it is larger than the sum of its proper divisors (1).

129253000531 is an equidigital number, since it uses as much as digits as its factorization.

129253000531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8100, while the sum is 31.

The spelling of 129253000531 in words is "one hundred twenty-nine billion, two hundred fifty-three million, five hundred thirty-one", and thus it is an aban number.