Base | Representation |
---|---|
bin | 11000000100111101… |
… | …00011011011011001 |
3 | 1020100212102111102212 |
4 | 30002132203123121 |
5 | 202433133401003 |
6 | 5534403004505 |
7 | 635221101035 |
oct | 140236433331 |
9 | 36325374385 |
10 | 12926465753 |
11 | 5533720053 |
12 | 2609069735 |
13 | 12b0096606 |
14 | 8a8aa71c5 |
15 | 509c78dd8 |
hex | 3027a36d9 |
12926465753 has 2 divisors, whose sum is σ = 12926465754. Its totient is φ = 12926465752.
The previous prime is 12926465723. The next prime is 12926465779. The reversal of 12926465753 is 35756462921.
12926465753 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9556431049 + 3370034704 = 97757^2 + 58052^2 .
It is a cyclic number.
It is not a de Polignac number, because 12926465753 - 26 = 12926465689 is a prime.
It is not a weakly prime, because it can be changed into another prime (12926465723) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6463232876 + 6463232877.
It is an arithmetic number, because the mean of its divisors is an integer number (6463232877).
Almost surely, 212926465753 is an apocalyptic number.
It is an amenable number.
12926465753 is a deficient number, since it is larger than the sum of its proper divisors (1).
12926465753 is an equidigital number, since it uses as much as digits as its factorization.
12926465753 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2721600, while the sum is 50.
The spelling of 12926465753 in words is "twelve billion, nine hundred twenty-six million, four hundred sixty-five thousand, seven hundred fifty-three".
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