1293000003941 has 2 divisors, whose sum is σ = 1293000003942. Its totient is φ = 1293000003940.

The previous prime is 1293000003871. The next prime is 1293000003959. The reversal of 1293000003941 is 1493000003921.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1029758152900 + 263241851041 = 1014770^2 + 513071^2 .

It is an emirp because it is prime and its reverse (1493000003921) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1293000003941 - 2¹⁴ = 1292999987557 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1293000003898 and 1293000003907.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1293000003241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 646500001970 + 646500001971.

It is an arithmetic number, because the mean of its divisors is an integer number (646500001971).

Almost surely, 2^{1293000003941} is an apocalyptic number.

It is an amenable number.

1293000003941 is a deficient number, since it is larger than the sum of its proper divisors (1).

1293000003941 is an equidigital number, since it uses as much as digits as its factorization.

1293000003941 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5832, while the sum is 32.

The spelling of 1293000003941 in words is "one trillion, two hundred ninety-three billion, three thousand, nine hundred forty-one".