Base | Representation |
---|---|
bin | 10010110100001111100… |
… | …100000001101100001111 |
3 | 11120121120121122210002201 |
4 | 102310033210001230033 |
5 | 132141124320232242 |
6 | 2430003420502331 |
7 | 162263614564366 |
oct | 22641744015417 |
9 | 4517517583081 |
10 | 1293046258447 |
11 | 4594179a3249 |
12 | 18a7266aa9a7 |
13 | 94c1a569878 |
14 | 46825c307dd |
15 | 2397d6e74b7 |
hex | 12d0f901b0f |
1293046258447 has 2 divisors, whose sum is σ = 1293046258448. Its totient is φ = 1293046258446.
The previous prime is 1293046258423. The next prime is 1293046258451. The reversal of 1293046258447 is 7448526403921.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1293046258447 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1293046258247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 646523129223 + 646523129224.
It is an arithmetic number, because the mean of its divisors is an integer number (646523129224).
It is a 1-persistent number, because it is pandigital, but 2⋅1293046258447 = 2586092516894 is not.
Almost surely, 21293046258447 is an apocalyptic number.
1293046258447 is a deficient number, since it is larger than the sum of its proper divisors (1).
1293046258447 is an equidigital number, since it uses as much as digits as its factorization.
1293046258447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11612160, while the sum is 55.
The spelling of 1293046258447 in words is "one trillion, two hundred ninety-three billion, forty-six million, two hundred fifty-eight thousand, four hundred forty-seven".
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