Base | Representation |
---|---|
bin | 1011110000110111111100… |
… | …0000011100001100000111 |
3 | 1200210111122000201222201212 |
4 | 2330031333000130030013 |
5 | 3143403400000201101 |
6 | 43301531444042035 |
7 | 2503320310321343 |
oct | 274157700341407 |
9 | 50714560658655 |
10 | 12934277350151 |
11 | 413743a406153 |
12 | 154a8bb39331b |
13 | 72a90a75c9b1 |
14 | 32a04551c623 |
15 | 1766b48341bb |
hex | bc37f01c307 |
12934277350151 has 2 divisors, whose sum is σ = 12934277350152. Its totient is φ = 12934277350150.
The previous prime is 12934277350097. The next prime is 12934277350301. The reversal of 12934277350151 is 15105377243921.
12934277350151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12934277350151 - 26 = 12934277350087 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12934277350151.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12934277350051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6467138675075 + 6467138675076.
It is an arithmetic number, because the mean of its divisors is an integer number (6467138675076).
Almost surely, 212934277350151 is an apocalyptic number.
12934277350151 is a deficient number, since it is larger than the sum of its proper divisors (1).
12934277350151 is an equidigital number, since it uses as much as digits as its factorization.
12934277350151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1587600, while the sum is 50.
The spelling of 12934277350151 in words is "twelve trillion, nine hundred thirty-four billion, two hundred seventy-seven million, three hundred fifty thousand, one hundred fifty-one".
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