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12935053877 = 41273134251
BaseRepresentation
bin11000000101111110…
…10100001000110101
31020101110120211010112
430002333110020311
5202442333211002
65535311032405
7635354100224
oct140277241065
936343524115
1012935053877
115538556479
12260bb0b705
1312b1ab2645
148a9ca0cbb
1550a8c3852
hex302fd4235

12935053877 has 4 divisors (see below), whose sum is σ = 12938192256. Its totient is φ = 12931915500.

The previous prime is 12935053811. The next prime is 12935053907. The reversal of 12935053877 is 77835053921.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12935053877 - 218 = 12934791733 is a prime.

It is a super-2 number, since 2×129350538772 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12935053777) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1562999 + ... + 1571252.

It is an arithmetic number, because the mean of its divisors is an integer number (3234548064).

Almost surely, 212935053877 is an apocalyptic number.

It is an amenable number.

12935053877 is a deficient number, since it is larger than the sum of its proper divisors (3138379).

12935053877 is an equidigital number, since it uses as much as digits as its factorization.

12935053877 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3138378.

The product of its (nonzero) digits is 1587600, while the sum is 50.

The spelling of 12935053877 in words is "twelve billion, nine hundred thirty-five million, fifty-three thousand, eight hundred seventy-seven".

Divisors: 1 4127 3134251 12935053877