Base | Representation |
---|---|
bin | 11000000110101001… |
… | …01100101101011011 |
3 | 1020101212010121122221 |
4 | 30003110230231123 |
5 | 203000302101142 |
6 | 5540031124511 |
7 | 635452535254 |
oct | 140324545533 |
9 | 36355117587 |
10 | 12940659547 |
11 | 5540735062 |
12 | 2611973737 |
13 | 12b2cc5cca |
14 | 8aa91db2b |
15 | 50b12e767 |
hex | 30352cb5b |
12940659547 has 2 divisors, whose sum is σ = 12940659548. Its totient is φ = 12940659546.
The previous prime is 12940659527. The next prime is 12940659559. The reversal of 12940659547 is 74595604921.
12940659547 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12940659547 - 27 = 12940659419 is a prime.
It is a super-2 number, since 2×129406595472 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12940659494 and 12940659503.
It is not a weakly prime, because it can be changed into another prime (12940659527) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6470329773 + 6470329774.
It is an arithmetic number, because the mean of its divisors is an integer number (6470329774).
Almost surely, 212940659547 is an apocalyptic number.
12940659547 is a deficient number, since it is larger than the sum of its proper divisors (1).
12940659547 is an equidigital number, since it uses as much as digits as its factorization.
12940659547 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2721600, while the sum is 52.
The spelling of 12940659547 in words is "twelve billion, nine hundred forty million, six hundred fifty-nine thousand, five hundred forty-seven".
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