Base | Representation |
---|---|
bin | 111100010001001010… |
… | …0100111111110100011 |
3 | 110101001211200122022111 |
4 | 1320202110213332203 |
5 | 4110030230211401 |
6 | 135242411420151 |
7 | 12231161036452 |
oct | 1704224477643 |
9 | 411054618274 |
10 | 129424850851 |
11 | 4a985a5505a |
12 | 21100154657 |
13 | c28799a2aa |
14 | 639ad50b99 |
15 | 3577603e51 |
hex | 1e22527fa3 |
129424850851 has 2 divisors, whose sum is σ = 129424850852. Its totient is φ = 129424850850.
The previous prime is 129424850843. The next prime is 129424850881. The reversal of 129424850851 is 158058424921.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 129424850851 - 23 = 129424850843 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 129424850795 and 129424850804.
It is not a weakly prime, because it can be changed into another prime (129424850881) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64712425425 + 64712425426.
It is an arithmetic number, because the mean of its divisors is an integer number (64712425426).
Almost surely, 2129424850851 is an apocalyptic number.
129424850851 is a deficient number, since it is larger than the sum of its proper divisors (1).
129424850851 is an equidigital number, since it uses as much as digits as its factorization.
129424850851 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 921600, while the sum is 49.
The spelling of 129424850851 in words is "one hundred twenty-nine billion, four hundred twenty-four million, eight hundred fifty thousand, eight hundred fifty-one".
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