Base | Representation |
---|---|
bin | 11000001000101001… |
… | …10111110010010011 |
3 | 1020110000210021220121 |
4 | 30010110313302103 |
5 | 203014103412011 |
6 | 5541431451111 |
7 | 636045531556 |
oct | 140424676223 |
9 | 36400707817 |
10 | 12957482131 |
11 | 554a185120 |
12 | 2617526a97 |
13 | 12b66360b9 |
14 | 8acc5c69d |
15 | 50c853e71 |
hex | 304537c93 |
12957482131 has 4 divisors (see below), whose sum is σ = 14135435064. Its totient is φ = 11779529200.
The previous prime is 12957482129. The next prime is 12957482149. The reversal of 12957482131 is 13128475921.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12957482131 - 21 = 12957482129 is a prime.
It is a super-2 number, since 2×129574821312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12957482171) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 588976450 + ... + 588976471.
It is an arithmetic number, because the mean of its divisors is an integer number (3533858766).
Almost surely, 212957482131 is an apocalyptic number.
12957482131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
12957482131 is a deficient number, since it is larger than the sum of its proper divisors (1177952933).
12957482131 is a wasteful number, since it uses less digits than its factorization.
12957482131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1177952932.
The product of its digits is 120960, while the sum is 43.
The spelling of 12957482131 in words is "twelve billion, nine hundred fifty-seven million, four hundred eighty-two thousand, one hundred thirty-one".
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