Base | Representation |
---|---|
bin | 10010110111101100111… |
… | …100100000100111111111 |
3 | 11120222011110112211012012 |
4 | 102313230330200213333 |
5 | 132221231133110333 |
6 | 2431420140401435 |
7 | 162454634612063 |
oct | 22675474404777 |
9 | 4528143484165 |
10 | 1296760441343 |
11 | 45aa5350a894 |
12 | 18b3a254627b |
13 | 9538cbb7c23 |
14 | 46a99223aa3 |
15 | 23ae9810e48 |
hex | 12decf209ff |
1296760441343 has 2 divisors, whose sum is σ = 1296760441344. Its totient is φ = 1296760441342.
The previous prime is 1296760441307. The next prime is 1296760441357. The reversal of 1296760441343 is 3431440676921.
It is a strong prime.
It is an emirp because it is prime and its reverse (3431440676921) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1296760441343 - 214 = 1296760424959 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1296760441291 and 1296760441300.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1296760441843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 648380220671 + 648380220672.
It is an arithmetic number, because the mean of its divisors is an integer number (648380220672).
Almost surely, 21296760441343 is an apocalyptic number.
1296760441343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1296760441343 is an equidigital number, since it uses as much as digits as its factorization.
1296760441343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2612736, while the sum is 50.
The spelling of 1296760441343 in words is "one trillion, two hundred ninety-six billion, seven hundred sixty million, four hundred forty-one thousand, three hundred forty-three".
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