Base | Representation |
---|---|
bin | 11000001011100110… |
… | …10110101000011011 |
3 | 1020111202101122001111 |
4 | 30011303112220123 |
5 | 203041424000021 |
6 | 5544114401151 |
7 | 636466206253 |
oct | 140563265033 |
9 | 36452348044 |
10 | 12982250011 |
11 | 5562161645 |
12 | 26238901b7 |
13 | 12bb7c8753 |
14 | 8b2268963 |
15 | 50eae78e1 |
hex | 305cd6a1b |
12982250011 has 2 divisors, whose sum is σ = 12982250012. Its totient is φ = 12982250010.
The previous prime is 12982249919. The next prime is 12982250077. The reversal of 12982250011 is 11005228921.
12982250011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (11005228921) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12982250011 - 211 = 12982247963 is a prime.
It is not a weakly prime, because it can be changed into another prime (12983250011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6491125005 + 6491125006.
It is an arithmetic number, because the mean of its divisors is an integer number (6491125006).
Almost surely, 212982250011 is an apocalyptic number.
12982250011 is a deficient number, since it is larger than the sum of its proper divisors (1).
12982250011 is an equidigital number, since it uses as much as digits as its factorization.
12982250011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 31.
Adding to 12982250011 its reverse (11005228921), we get a palindrome (23987478932).
The spelling of 12982250011 in words is "twelve billion, nine hundred eighty-two million, two hundred fifty thousand, eleven".
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