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1298750423093 is a prime number
BaseRepresentation
bin10010111001100011100…
…011101100000000110101
311121011022011001100221222
4102321203203230000311
5132234320102014333
62432345424520125
7162555150310124
oct22714343540065
94534264040858
101298750423093
11460884834602
1218b858a80045
1395619265316
1446c07631abb
1523bb4395298
hex12e638ec035

1298750423093 has 2 divisors, whose sum is σ = 1298750423094. Its totient is φ = 1298750423092.

The previous prime is 1298750423051. The next prime is 1298750423111. The reversal of 1298750423093 is 3903240578921.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1002197205604 + 296553217489 = 1001098^2 + 544567^2 .

It is a cyclic number.

It is not a de Polignac number, because 1298750423093 - 212 = 1298750418997 is a prime.

It is a super-2 number, since 2×12987504230932 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1298750423023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 649375211546 + 649375211547.

It is an arithmetic number, because the mean of its divisors is an integer number (649375211547).

Almost surely, 21298750423093 is an apocalyptic number.

It is an amenable number.

1298750423093 is a deficient number, since it is larger than the sum of its proper divisors (1).

1298750423093 is an equidigital number, since it uses as much as digits as its factorization.

1298750423093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3265920, while the sum is 53.

The spelling of 1298750423093 in words is "one trillion, two hundred ninety-eight billion, seven hundred fifty million, four hundred twenty-three thousand, ninety-three".