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1299038245413 = 32116812045591
BaseRepresentation
bin10010111001110100101…
…101101001001000100101
311121012001012122020221220
4102321310231221020211
5132240412242323123
62432434145530553
7162565243620216
oct22716455511045
94535035566856
101299038245413
11460a12250797
1218b919343a59
1395663a8b29c
1446c3395540d
1523bce79ace3
hex12e74b69225

1299038245413 has 8 divisors (see below), whose sum is σ = 1732060022976. Its totient is φ = 866020982400.

The previous prime is 1299038245409. The next prime is 1299038245441. The reversal of 1299038245413 is 3145428309921.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1299038245413 - 22 = 1299038245409 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1299038245013) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 387753 + ... + 1657838.

It is an arithmetic number, because the mean of its divisors is an integer number (216507502872).

Almost surely, 21299038245413 is an apocalyptic number.

It is an amenable number.

1299038245413 is a deficient number, since it is larger than the sum of its proper divisors (433021777563).

1299038245413 is a wasteful number, since it uses less digits than its factorization.

1299038245413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2257275.

The product of its (nonzero) digits is 1866240, while the sum is 51.

It can be divided in two parts, 1299038 and 245413, that added together give a palindrome (1544451).

The spelling of 1299038245413 in words is "one trillion, two hundred ninety-nine billion, thirty-eight million, two hundred forty-five thousand, four hundred thirteen".

Divisors: 1 3 211681 635043 2045591 6136773 433012748471 1299038245413