Base | Representation |
---|---|
bin | 11000001100100101… |
… | …01000010111011001 |
3 | 1020112022211012002221 |
4 | 30012102220113121 |
5 | 203101023332423 |
6 | 5545010224041 |
7 | 636625665325 |
oct | 140622502731 |
9 | 36468735087 |
10 | 12990449113 |
11 | 5566851764 |
12 | 2626585021 |
13 | 12c04096a5 |
14 | 8b33a0985 |
15 | 5106b6e5d |
hex | 3064a85d9 |
12990449113 has 2 divisors, whose sum is σ = 12990449114. Its totient is φ = 12990449112.
The previous prime is 12990449083. The next prime is 12990449117. The reversal of 12990449113 is 31194409921.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8688663369 + 4301785744 = 93213^2 + 65588^2 .
It is a cyclic number.
It is not a de Polignac number, because 12990449113 - 213 = 12990440921 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12990449113.
It is not a weakly prime, because it can be changed into another prime (12990449117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6495224556 + 6495224557.
It is an arithmetic number, because the mean of its divisors is an integer number (6495224557).
Almost surely, 212990449113 is an apocalyptic number.
It is an amenable number.
12990449113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12990449113 is an equidigital number, since it uses as much as digits as its factorization.
12990449113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69984, while the sum is 43.
The spelling of 12990449113 in words is "twelve billion, nine hundred ninety million, four hundred forty-nine thousand, one hundred thirteen".
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