Base | Representation |
---|---|
bin | 11101100011101111111011… |
… | …110100100010000001100011 |
3 | 122001021212201112000021220111 |
4 | 131203233323310202001203 |
5 | 114014410000000000344 |
6 | 1140253101525552151 |
7 | 36245122121541655 |
oct | 3543577364420143 |
9 | 561255645007814 |
10 | 130000000000099 |
11 | 384707659a8309 |
12 | 126b6a54b75657 |
13 | 576cc41585248 |
14 | 241606819c6d5 |
15 | 10068e9598834 |
hex | 763bfbd22063 |
130000000000099 has 2 divisors, whose sum is σ = 130000000000100. Its totient is φ = 130000000000098.
The previous prime is 130000000000063. The next prime is 130000000000109. The reversal of 130000000000099 is 990000000000031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130000000000099 - 241 = 127800976744547 is a prime.
It is not a weakly prime, because it can be changed into another prime (130000000000699) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000000000049 + 65000000000050.
It is an arithmetic number, because the mean of its divisors is an integer number (65000000000050).
Almost surely, 2130000000000099 is an apocalyptic number.
130000000000099 is a deficient number, since it is larger than the sum of its proper divisors (1).
130000000000099 is an equidigital number, since it uses as much as digits as its factorization.
130000000000099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 22.
The spelling of 130000000000099 in words is "one hundred thirty trillion, ninety-nine", and thus it is an aban number.
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