130000000000063 has 2 divisors, whose sum is σ = 130000000000064. Its totient is φ = 130000000000062.

The previous prime is 129999999999973. The next prime is 130000000000099. The reversal of 130000000000063 is 360000000000031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130000000000063 - 2¹³ = 129999999991871 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 129999999999953 and 130000000000052.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130000000003063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000000000031 + 65000000000032.

It is an arithmetic number, because the mean of its divisors is an integer number (65000000000032).

Almost surely, 2^{130000000000063} is an apocalyptic number.

130000000000063 is a deficient number, since it is larger than the sum of its proper divisors (1).

130000000000063 is an equidigital number, since it uses as much as digits as its factorization.

130000000000063 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 130000000000063 its reverse (360000000000031), we get a palindrome (490000000000094).

The spelling of 130000000000063 in words is "one hundred thirty trillion, sixty-three", and thus it is an aban number.