1300000213313 has 2 divisors, whose sum is σ = 1300000213314. Its totient is φ = 1300000213312.

The previous prime is 1300000213301. The next prime is 1300000213333. The reversal of 1300000213313 is 3133120000031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1137951295504 + 162048917809 = 1066748^2 + 402553^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1300000213313 is a prime.

It is a super-2 number, since 2×1300000213313² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1300000213291 and 1300000213300.

It is not a weakly prime, because it can be changed into another prime (1300000213333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650000106656 + 650000106657.

It is an arithmetic number, because the mean of its divisors is an integer number (650000106657).

Almost surely, 2^{1300000213313} is an apocalyptic number.

It is an amenable number.

1300000213313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300000213313 is an equidigital number, since it uses as much as digits as its factorization.

1300000213313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 1300000213313 its reverse (3133120000031), we get a palindrome (4433120213344).

The spelling of 1300000213313 in words is "one trillion, three hundred billion, two hundred thirteen thousand, three hundred thirteen".