13000002341323 has 4 divisors (see below), whose sum is σ = 13565219834448. Its totient is φ = 12434784848200.

The previous prime is 13000002341281. The next prime is 13000002341353. The reversal of 13000002341323 is 32314320000031.

13000002341323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13000002341323 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13000002341294 and 13000002341303.

It is not an unprimeable number, because it can be changed into a prime (13000002341353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 282608746528 + ... + 282608746573.

It is an arithmetic number, because the mean of its divisors is an integer number (3391304958612).

Almost surely, 2^{13000002341323} is an apocalyptic number.

13000002341323 is a deficient number, since it is larger than the sum of its proper divisors (565217493125).

13000002341323 is an equidigital number, since it uses as much as digits as its factorization.

13000002341323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 565217493124.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 13000002341323 its reverse (32314320000031), we get a palindrome (45314322341354).

The spelling of 13000002341323 in words is "thirteen trillion, two million, three hundred forty-one thousand, three hundred twenty-three".