130000043441442 has 8 divisors (see below), whose sum is σ = 260000086882896. Its totient is φ = 43333347813812.

The previous prime is 130000043441441. The next prime is 130000043441483. The reversal of 130000043441442 is 244144340000031.

130000043441442 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

130000043441442 is an admirable number.

It is a super-2 number, since 2×130000043441442² (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (130000043441441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10833336953448 + ... + 10833336953459.

It is an arithmetic number, because the mean of its divisors is an integer number (32500010860362).

Almost surely, 2^{130000043441442} is an apocalyptic number.

130000043441442 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130000043441442 is a wasteful number, since it uses less digits than its factorization.

130000043441442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21666673906912.

The product of its (nonzero) digits is 18432, while the sum is 30.

Adding to 130000043441442 its reverse (244144340000031), we get a palindrome (374144383441473).

The spelling of 130000043441442 in words is "one hundred thirty trillion, forty-three million, four hundred forty-one thousand, four hundred forty-two".