Search a number
-
+
1300001011 = 79149110441
BaseRepresentation
bin100110101111100…
…0111000011110011
310100121011220010121
41031133013003303
510130300013021
6332555311111
744133553261
oct11537070363
93317156117
101300001011
116078a9001
1230344b497
1317943858a
14c4921431
15791e0741
hex4d7c70f3

1300001011 has 8 divisors (see below), whose sum is σ = 1325304000. Its totient is φ = 1274919360.

The previous prime is 1300000991. The next prime is 1300001039. The reversal of 1300001011 is 1101000031.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1300001011 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1300000985 and 1300001003.

It is not an unprimeable number, because it can be changed into a prime (1300001041) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43450 + ... + 66991.

It is an arithmetic number, because the mean of its divisors is an integer number (165663000).

Almost surely, 21300001011 is an apocalyptic number.

1300001011 is a deficient number, since it is larger than the sum of its proper divisors (25302989).

1300001011 is a wasteful number, since it uses less digits than its factorization.

1300001011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 110669.

The product of its (nonzero) digits is 3, while the sum is 7.

The square root of 1300001011 is about 36055.5267746846. The cubic root of 1300001011 is about 1091.3931659836.

Adding to 1300001011 its reverse (1101000031), we get a palindrome (2401001042).

The spelling of 1300001011 in words is "one billion, three hundred million, one thousand, eleven".

Divisors: 1 79 149 11771 110441 8724839 16455709 1300001011