Base | Representation |
---|---|
bin | 1011110100101100110011… |
… | …1111100000110001010001 |
3 | 1201000210022001202201121211 |
4 | 2331023030333200301101 |
5 | 3200443010110122212 |
6 | 43352042224020121 |
7 | 2511135241545022 |
oct | 275131477406121 |
9 | 51023261681554 |
10 | 13000010239057 |
11 | 4162300963526 |
12 | 155b5a5161641 |
13 | 733b84b31a2a |
14 | 32d2bd52cc49 |
15 | 17826050a9a7 |
hex | bd2ccfe0c51 |
13000010239057 has 2 divisors, whose sum is σ = 13000010239058. Its totient is φ = 13000010239056.
The previous prime is 13000010239049. The next prime is 13000010239061. The reversal of 13000010239057 is 75093201000031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12830036265216 + 169973973841 = 3581904^2 + 412279^2 .
It is a cyclic number.
It is not a de Polignac number, because 13000010239057 - 23 = 13000010239049 is a prime.
It is not a weakly prime, because it can be changed into another prime (13000010231057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500005119528 + 6500005119529.
It is an arithmetic number, because the mean of its divisors is an integer number (6500005119529).
Almost surely, 213000010239057 is an apocalyptic number.
It is an amenable number.
13000010239057 is a deficient number, since it is larger than the sum of its proper divisors (1).
13000010239057 is an equidigital number, since it uses as much as digits as its factorization.
13000010239057 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5670, while the sum is 31.
Adding to 13000010239057 its reverse (75093201000031), we get a palindrome (88093211239088).
The spelling of 13000010239057 in words is "thirteen trillion, ten million, two hundred thirty-nine thousand, fifty-seven".
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