1300001213311 has 2 divisors, whose sum is σ = 1300001213312. Its totient is φ = 1300001213310.

The previous prime is 1300001213297. The next prime is 1300001213323. The reversal of 1300001213311 is 1133121000031.

It is a strong prime.

It is an emirp because it is prime and its reverse (1133121000031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1300001213311 - 2¹¹ = 1300001211263 is a prime.

It is a super-2 number, since 2×1300001213311² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300001219311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650000606655 + 650000606656.

It is an arithmetic number, because the mean of its divisors is an integer number (650000606656).

Almost surely, 2^{1300001213311} is an apocalyptic number.

1300001213311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300001213311 is an equidigital number, since it uses as much as digits as its factorization.

1300001213311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1300001213311 its reverse (1133121000031), we get a palindrome (2433122213342).

The spelling of 1300001213311 in words is "one trillion, three hundred billion, one million, two hundred thirteen thousand, three hundred eleven".