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130000212211 = 831566267617
BaseRepresentation
bin111100100010010011…
…1011101000011110011
3110102112221100000201111
41321010213131003303
54112220023242321
6135415443414151
712251345400022
oct1710447350363
9412487300644
10130000212211
1150150804611
1221240984357
13c349c4a2bc
1464135228b9
1535acda65e1
hex1e449dd0f3

130000212211 has 4 divisors (see below), whose sum is σ = 131566479912. Its totient is φ = 128433944512.

The previous prime is 130000212191. The next prime is 130000212247. The reversal of 130000212211 is 112212000031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130000212211 - 211 = 130000210163 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130000212191 and 130000212200.

It is not an unprimeable number, because it can be changed into a prime (130000212271) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 783133726 + ... + 783133891.

It is an arithmetic number, because the mean of its divisors is an integer number (32891619978).

Almost surely, 2130000212211 is an apocalyptic number.

130000212211 is a deficient number, since it is larger than the sum of its proper divisors (1566267701).

130000212211 is an equidigital number, since it uses as much as digits as its factorization.

130000212211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1566267700.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 130000212211 its reverse (112212000031), we get a palindrome (242212212242).

The spelling of 130000212211 in words is "one hundred thirty billion, two hundred twelve thousand, two hundred eleven".

Divisors: 1 83 1566267617 130000212211