Base | Representation |
---|---|
bin | 111100100010010011… |
… | …1011101100101001011 |
3 | 110102112221100010122121 |
4 | 1321010213131211023 |
5 | 4112220023324342 |
6 | 135415443432111 |
7 | 12251345406163 |
oct | 1710447354513 |
9 | 412487303577 |
10 | 130000214347 |
11 | 50150806183 |
12 | 21240985637 |
13 | c349c4b273 |
14 | 64135235a3 |
15 | 35acda7067 |
hex | 1e449dd94b |
130000214347 has 2 divisors, whose sum is σ = 130000214348. Its totient is φ = 130000214346.
The previous prime is 130000214321. The next prime is 130000214401. The reversal of 130000214347 is 743412000031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130000214347 - 223 = 129991825739 is a prime.
It is not a weakly prime, because it can be changed into another prime (130000214947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000107173 + 65000107174.
It is an arithmetic number, because the mean of its divisors is an integer number (65000107174).
Almost surely, 2130000214347 is an apocalyptic number.
130000214347 is a deficient number, since it is larger than the sum of its proper divisors (1).
130000214347 is an equidigital number, since it uses as much as digits as its factorization.
130000214347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 25.
Adding to 130000214347 its reverse (743412000031), we get a palindrome (873412214378).
The spelling of 130000214347 in words is "one hundred thirty billion, two hundred fourteen thousand, three hundred forty-seven".
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