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130000231303109 is a prime number
BaseRepresentation
bin11101100011110000001001…
…100110111000011111000101
3122001021220022122020200222122
4131203300021212320133011
5114014410433203144414
61140253140511335325
736245130630562526
oct3543601146703705
9561256278220878
10130000231303109
1138470874520722
12126b6aba521545
13576cc7a47c62b
14241608abac84d
15100690ea37b8e
hex763c099b87c5

130000231303109 has 2 divisors, whose sum is σ = 130000231303110. Its totient is φ = 130000231303108.

The previous prime is 130000231303099. The next prime is 130000231303127. The reversal of 130000231303109 is 901303132000031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 128962029261025 + 1038202042084 = 11356145^2 + 1018922^2 .

It is an emirp because it is prime and its reverse (901303132000031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130000231303109 - 212 = 130000231299013 is a prime.

It is a super-2 number, since 2×1300002313031092 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130000231303199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000115651554 + 65000115651555.

It is an arithmetic number, because the mean of its divisors is an integer number (65000115651555).

Almost surely, 2130000231303109 is an apocalyptic number.

It is an amenable number.

130000231303109 is a deficient number, since it is larger than the sum of its proper divisors (1).

130000231303109 is an equidigital number, since it uses as much as digits as its factorization.

130000231303109 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 26.

The spelling of 130000231303109 in words is "one hundred thirty trillion, two hundred thirty-one million, three hundred three thousand, one hundred nine".