Base | Representation |
---|---|
bin | 11101100011110000111000… |
… | …110000010011001111011111 |
3 | 122001021222100202122120022102 |
4 | 131203300320300103033133 |
5 | 114014414043202114101 |
6 | 1140253351205235315 |
7 | 36245156344134341 |
oct | 3543607060231737 |
9 | 561258322576272 |
10 | 130001022301151 |
11 | 3847113aa73211 |
12 | 126b709b402b3b |
13 | 5770075300001 |
14 | 2416123c73291 |
15 | 10069591d286b |
hex | 763c38c133df |
130001022301151 has 2 divisors, whose sum is σ = 130001022301152. Its totient is φ = 130001022301150.
The previous prime is 130001022301133. The next prime is 130001022301219. The reversal of 130001022301151 is 151103220100031.
It is a weak prime.
It is an emirp because it is prime and its reverse (151103220100031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130001022301151 - 222 = 130001018106847 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130001022303151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000511150575 + 65000511150576.
It is an arithmetic number, because the mean of its divisors is an integer number (65000511150576).
Almost surely, 2130001022301151 is an apocalyptic number.
130001022301151 is a deficient number, since it is larger than the sum of its proper divisors (1).
130001022301151 is an equidigital number, since it uses as much as digits as its factorization.
130001022301151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 180, while the sum is 20.
Adding to 130001022301151 its reverse (151103220100031), we get a palindrome (281104242401182).
The spelling of 130001022301151 in words is "one hundred thirty trillion, one billion, twenty-two million, three hundred one thousand, one hundred fifty-one".
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