1300011107 has 2 divisors, whose sum is σ = 1300011108. Its totient is φ = 1300011106.

The previous prime is 1300011079. The next prime is 1300011121. The reversal of 1300011107 is 7011100031.

It is an a-pointer prime, because the next prime (1300011121) can be obtained adding 1300011107 to its sum of digits (14).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1300011107 - 2⁸ = 1300010851 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1300011091 and 1300011100.

It is not a weakly prime, because it can be changed into another prime (1300011127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650005553 + 650005554.

It is an arithmetic number, because the mean of its divisors is an integer number (650005554).

Almost surely, 2^1300011107 is an apocalyptic number.

1300011107 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300011107 is an equidigital number, since it uses as much as digits as its factorization.

1300011107 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21, while the sum is 14.

The square root of 1300011107 is about 36055.6667806879. Note that the first 3 decimals coincide. The cubic root of 1300011107 is about 1091.3959912832.

Adding to 1300011107 its reverse (7011100031), we get a palindrome (8311111138).

The spelling of 1300011107 in words is "one billion, three hundred million, eleven thousand, one hundred seven".