Base | Representation |
---|---|
bin | 11000001101101111… |
… | …00000001110101010 |
3 | 1020120000000021100222 |
4 | 30012313200032222 |
5 | 203111012140424 |
6 | 5545553330042 |
7 | 640104104150 |
oct | 140667401652 |
9 | 36500007328 |
10 | 13000115114 |
11 | 5571253998 |
12 | 2629866922 |
13 | 12c241220c |
14 | 8b47993d0 |
15 | 511475e5e |
hex | 306de03aa |
13000115114 has 16 divisors (see below), whose sum is σ = 22289985600. Its totient is φ = 5570459424.
The previous prime is 13000115113. The next prime is 13000115147. The reversal of 13000115114 is 41151100031.
It is a junction number, because it is equal to n+sod(n) for n = 13000115092 and 13000115101.
It is not an unprimeable number, because it can be changed into a prime (13000115113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2819 + ... + 161270.
It is an arithmetic number, because the mean of its divisors is an integer number (1393124100).
Almost surely, 213000115114 is an apocalyptic number.
13000115114 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
13000115114 is a deficient number, since it is larger than the sum of its proper divisors (9289870486).
13000115114 is a wasteful number, since it uses less digits than its factorization.
13000115114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 169757.
The product of its (nonzero) digits is 60, while the sum is 17.
Adding to 13000115114 its reverse (41151100031), we get a palindrome (54151215145).
The spelling of 13000115114 in words is "thirteen billion, one hundred fifteen thousand, one hundred fourteen".
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