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13000115147 is a prime number
BaseRepresentation
bin11000001101101111…
…00000001111001011
31020120000000021102012
430012313200033023
5203111012141042
65545553330135
7640104104225
oct140667401713
936500007365
1013000115147
115571253a18
12262986694b
1312c2412236
148b4799415
15511475e82
hex306de03cb

13000115147 has 2 divisors, whose sum is σ = 13000115148. Its totient is φ = 13000115146.

The previous prime is 13000115113. The next prime is 13000115173. The reversal of 13000115147 is 74151100031.

It is a happy number.

13000115147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13000115147 - 26 = 13000115083 is a prime.

It is not a weakly prime, because it can be changed into another prime (13000165147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500057573 + 6500057574.

It is an arithmetic number, because the mean of its divisors is an integer number (6500057574).

Almost surely, 213000115147 is an apocalyptic number.

13000115147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000115147 is an equidigital number, since it uses as much as digits as its factorization.

13000115147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 420, while the sum is 23.

Adding to 13000115147 its reverse (74151100031), we get a palindrome (87151215178).

The spelling of 13000115147 in words is "thirteen billion, one hundred fifteen thousand, one hundred forty-seven".