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130001203249 is a prime number
BaseRepresentation
bin111100100010010101…
…1001111000000110001
3110102120000012101011121
41321010223033000301
54112220302000444
6135415520542241
712251356665241
oct1710453170061
9412500171147
10130001203249
1150151321155
1221241181981
13c34a206408
1464136ddb21
1535ad000084
hex1e44acf031

130001203249 has 2 divisors, whose sum is σ = 130001203250. Its totient is φ = 130001203248.

The previous prime is 130001203237. The next prime is 130001203349. The reversal of 130001203249 is 942302100031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 126403003024 + 3598200225 = 355532^2 + 59985^2 .

It is an emirp because it is prime and its reverse (942302100031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130001203249 - 27 = 130001203121 is a prime.

It is not a weakly prime, because it can be changed into another prime (130001203349) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000601624 + 65000601625.

It is an arithmetic number, because the mean of its divisors is an integer number (65000601625).

Almost surely, 2130001203249 is an apocalyptic number.

It is an amenable number.

130001203249 is a deficient number, since it is larger than the sum of its proper divisors (1).

130001203249 is an equidigital number, since it uses as much as digits as its factorization.

130001203249 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

The spelling of 130001203249 in words is "one hundred thirty billion, one million, two hundred three thousand, two hundred forty-nine".