1300013211131 has 2 divisors, whose sum is σ = 1300013211132. Its totient is φ = 1300013211130.

The previous prime is 1300013211113. The next prime is 1300013211139. The reversal of 1300013211131 is 1311123100031.

Together with previous prime (1300013211113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1300013211131 - 2²² = 1300009016827 is a prime.

It is a super-2 number, since 2×1300013211131² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1300013211139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650006605565 + 650006605566.

It is an arithmetic number, because the mean of its divisors is an integer number (650006605566).

Almost surely, 2^{1300013211131} is an apocalyptic number.

1300013211131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300013211131 is an equidigital number, since it uses as much as digits as its factorization.

1300013211131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1300013211131 its reverse (1311123100031), we get a palindrome (2611136311162).

The spelling of 1300013211131 in words is "one trillion, three hundred billion, thirteen million, two hundred eleven thousand, one hundred thirty-one".