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13000132211023 = 121474310701961
BaseRepresentation
bin1011110100101101010001…
…0000110011000101001111
31201000210121120021112201001
42331023110100303011033
53200443232321223043
643352102302201131
72511141252361306
oct275132420630517
951023546245631
1013000132211023
1141623637a1901
12155b619b831a7
13733ba41993a9
1432d2d17dd43d
1517826b0a074d
hexbd2d443314f

13000132211023 has 4 divisors (see below), whose sum is σ = 13000144127728. Its totient is φ = 13000120294320.

The previous prime is 13000132210997. The next prime is 13000132211063. The reversal of 13000132211023 is 32011223100031.

13000132211023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13000132211023 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13000132211063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4136238 + ... + 6565723.

It is an arithmetic number, because the mean of its divisors is an integer number (3250036031932).

Almost surely, 213000132211023 is an apocalyptic number.

13000132211023 is a deficient number, since it is larger than the sum of its proper divisors (11916705).

13000132211023 is a wasteful number, since it uses less digits than its factorization.

13000132211023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11916704.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13000132211023 its reverse (32011223100031), we get a palindrome (45011355311054).

The spelling of 13000132211023 in words is "thirteen trillion, one hundred thirty-two million, two hundred eleven thousand, twenty-three".

Divisors: 1 1214743 10701961 13000132211023