Base | Representation |
---|---|
bin | 1011110100101101010001… |
… | …0000110011000101001111 |
3 | 1201000210121120021112201001 |
4 | 2331023110100303011033 |
5 | 3200443232321223043 |
6 | 43352102302201131 |
7 | 2511141252361306 |
oct | 275132420630517 |
9 | 51023546245631 |
10 | 13000132211023 |
11 | 41623637a1901 |
12 | 155b619b831a7 |
13 | 733ba41993a9 |
14 | 32d2d17dd43d |
15 | 17826b0a074d |
hex | bd2d443314f |
13000132211023 has 4 divisors (see below), whose sum is σ = 13000144127728. Its totient is φ = 13000120294320.
The previous prime is 13000132210997. The next prime is 13000132211063. The reversal of 13000132211023 is 32011223100031.
13000132211023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13000132211023 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13000132211063) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4136238 + ... + 6565723.
It is an arithmetic number, because the mean of its divisors is an integer number (3250036031932).
Almost surely, 213000132211023 is an apocalyptic number.
13000132211023 is a deficient number, since it is larger than the sum of its proper divisors (11916705).
13000132211023 is a wasteful number, since it uses less digits than its factorization.
13000132211023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11916704.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 13000132211023 its reverse (32011223100031), we get a palindrome (45011355311054).
The spelling of 13000132211023 in words is "thirteen trillion, one hundred thirty-two million, two hundred eleven thousand, twenty-three".
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