130001343633 has 32 divisors (see below), whose sum is σ = 220731744000. Its totient is φ = 74076000768.

The previous prime is 130001343631. The next prime is 130001343643. The reversal of 130001343633 is 336343100031.

130001343633 is a `hidden beast` number, since 13 + 0 + 0 + 0 + 13 + 4 + 3 + 633 = 666.

It is not a de Polignac number, because 130001343633 - 2¹ = 130001343631 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 130001343597 and 130001343606.

It is not an unprimeable number, because it can be changed into a prime (130001343631) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 907558 + ... + 1040991.

It is an arithmetic number, because the mean of its divisors is an integer number (6897867000).

Almost surely, 2^130001343633 is an apocalyptic number.

It is an amenable number.

130001343633 is a deficient number, since it is larger than the sum of its proper divisors (90730400367).

130001343633 is a wasteful number, since it uses less digits than its factorization.

130001343633 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1948918 (or 1948912 counting only the distinct ones).

The product of its (nonzero) digits is 5832, while the sum is 27.

Adding to 130001343633 its reverse (336343100031), we get a palindrome (466344443664).

The spelling of 130001343633 in words is "one hundred thirty billion, one million, three hundred forty-three thousand, six hundred thirty-three".