1300013442233 has 4 divisors (see below), whose sum is σ = 1418196482448. Its totient is φ = 1181830402020.

The previous prime is 1300013442209. The next prime is 1300013442289. The reversal of 1300013442233 is 3322443100031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1300013442233 - 2¹² = 1300013438137 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1300013448233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59091520091 + ... + 59091520112.

It is an arithmetic number, because the mean of its divisors is an integer number (354549120612).

Almost surely, 2^{1300013442233} is an apocalyptic number.

It is an amenable number.

1300013442233 is a deficient number, since it is larger than the sum of its proper divisors (118183040215).

1300013442233 is a wasteful number, since it uses less digits than its factorization.

1300013442233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 118183040214.

The product of its (nonzero) digits is 5184, while the sum is 26.

Adding to 1300013442233 its reverse (3322443100031), we get a palindrome (4622456542264).

The spelling of 1300013442233 in words is "one trillion, three hundred billion, thirteen million, four hundred forty-two thousand, two hundred thirty-three".