1300014131 has 4 divisors (see below), whose sum is σ = 1400015232. Its totient is φ = 1200013032.

The previous prime is 1300014097. The next prime is 1300014139. The reversal of 1300014131 is 1314100031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1314100031 = 97 ⋅13547423.

It is a cyclic number.

It is not a de Polignac number, because 1300014131 - 2¹⁴ = 1299997747 is a prime.

It is a super-2 number, since 2×1300014131² = 3380073481599370322, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300014139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50000531 + ... + 50000556.

It is an arithmetic number, because the mean of its divisors is an integer number (350003808).

Almost surely, 2^1300014131 is an apocalyptic number.

1300014131 is a deficient number, since it is larger than the sum of its proper divisors (100001101).

1300014131 is a wasteful number, since it uses less digits than its factorization.

1300014131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100001100.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 1300014131 is about 36055.7087158192. The cubic root of 1300014131 is about 1091.3968375270.

Adding to 1300014131 its reverse (1314100031), we get a palindrome (2614114162).

The spelling of 1300014131 in words is "one billion, three hundred million, fourteen thousand, one hundred thirty-one".