Base | Representation |
---|---|
bin | 111100100010010111… |
… | …0010100101110101111 |
3 | 110102120001201112002012 |
4 | 1321010232110232233 |
5 | 4112221003404403 |
6 | 135415550151435 |
7 | 12251366610314 |
oct | 1710456245657 |
9 | 412501645065 |
10 | 130002013103 |
11 | 50151824656 |
12 | 212414b257b |
13 | c34a42ac11 |
14 | 6413870d0b |
15 | 35ad10eed8 |
hex | 1e44b94baf |
130002013103 has 2 divisors, whose sum is σ = 130002013104. Its totient is φ = 130002013102.
The previous prime is 130002013069. The next prime is 130002013147. The reversal of 130002013103 is 301310200031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130002013103 - 26 = 130002013039 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130002013303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65001006551 + 65001006552.
It is an arithmetic number, because the mean of its divisors is an integer number (65001006552).
Almost surely, 2130002013103 is an apocalyptic number.
130002013103 is a deficient number, since it is larger than the sum of its proper divisors (1).
130002013103 is an equidigital number, since it uses as much as digits as its factorization.
130002013103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 130002013103 its reverse (301310200031), we get a palindrome (431312213134).
The spelling of 130002013103 in words is "one hundred thirty billion, two million, thirteen thousand, one hundred three".
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