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13000202212222 = 26500101106111
BaseRepresentation
bin1011110100101101100001…
…1011110101001101111110
31201000210210102222222022001
42331023120123311031332
53200443403231242342
643352113242412514
72511143062361401
oct275133033651576
951023712888261
1013000202212222
11416239a263835
12155b63950113a
13733bb5838614
1432d2dac21d38
151782722cb8b7
hexbd2d86f537e

13000202212222 has 4 divisors (see below), whose sum is σ = 19500303318336. Its totient is φ = 6500101106110.

The previous prime is 13000202212169. The next prime is 13000202212223. The reversal of 13000202212222 is 22221220200031.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 13000202212222.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13000202212223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3250050553054 + ... + 3250050553057.

It is an arithmetic number, because the mean of its divisors is an integer number (4875075829584).

Almost surely, 213000202212222 is an apocalyptic number.

13000202212222 is a deficient number, since it is larger than the sum of its proper divisors (6500101106114).

13000202212222 is an equidigital number, since it uses as much as digits as its factorization.

13000202212222 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6500101106113.

The product of its (nonzero) digits is 384, while the sum is 19.

Adding to 13000202212222 its reverse (22221220200031), we get a palindrome (35221422412253).

The spelling of 13000202212222 in words is "thirteen trillion, two hundred two million, two hundred twelve thousand, two hundred twenty-two".

Divisors: 1 2 6500101106111 13000202212222