130002101113 has 4 divisors (see below), whose sum is σ = 130120609140. Its totient is φ = 129883593088.

The previous prime is 130002101101. The next prime is 130002101129. The reversal of 130002101113 is 311101200031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 42013930729 + 87988170384 = 204973^2 + 296628^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130002101113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130002101093 and 130002101102.

It is not an unprimeable number, because it can be changed into a prime (130002101153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59252368 + ... + 59254561.

It is an arithmetic number, because the mean of its divisors is an integer number (32530152285).

Almost surely, 2^130002101113 is an apocalyptic number.

It is an amenable number.

130002101113 is a deficient number, since it is larger than the sum of its proper divisors (118508027).

130002101113 is a wasteful number, since it uses less digits than its factorization.

130002101113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 118508026.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 130002101113 its reverse (311101200031), we get a palindrome (441103301144).

The spelling of 130002101113 in words is "one hundred thirty billion, two million, one hundred one thousand, one hundred thirteen".