13000210130023 has 2 divisors, whose sum is σ = 13000210130024. Its totient is φ = 13000210130022.

The previous prime is 13000210130009. The next prime is 13000210130059. The reversal of 13000210130023 is 32003101200031.

13000210130023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13000210130023 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13000210129979 and 13000210130006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13000210130003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500105065011 + 6500105065012.

It is an arithmetic number, because the mean of its divisors is an integer number (6500105065012).

Almost surely, 2^{13000210130023} is an apocalyptic number.

13000210130023 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000210130023 is an equidigital number, since it uses as much as digits as its factorization.

13000210130023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 13000210130023 its reverse (32003101200031), we get a palindrome (45003311330054).

The spelling of 13000210130023 in words is "thirteen trillion, two hundred ten million, one hundred thirty thousand, twenty-three".