Base | Representation |
---|---|
bin | 11000001101101111… |
… | …10111011110000101 |
3 | 1020120000012002221201 |
4 | 30012313313132011 |
5 | 203111023212214 |
6 | 5545555342501 |
7 | 640104651532 |
oct | 140667673605 |
9 | 36500162851 |
10 | 13000210309 |
11 | 5571309469 |
12 | 26298b1a31 |
13 | 12c2446648 |
14 | 8b47c1d89 |
15 | 511494274 |
hex | 306df7785 |
13000210309 has 2 divisors, whose sum is σ = 13000210310. Its totient is φ = 13000210308.
The previous prime is 13000210297. The next prime is 13000210441. The reversal of 13000210309 is 90301200031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12973893409 + 26316900 = 113903^2 + 5130^2 .
It is a cyclic number.
It is not a de Polignac number, because 13000210309 - 223 = 12991821701 is a prime.
It is a super-3 number, since 3×130002103093 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13000214309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500105154 + 6500105155.
It is an arithmetic number, because the mean of its divisors is an integer number (6500105155).
Almost surely, 213000210309 is an apocalyptic number.
It is an amenable number.
13000210309 is a deficient number, since it is larger than the sum of its proper divisors (1).
13000210309 is an equidigital number, since it uses as much as digits as its factorization.
13000210309 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
The spelling of 13000210309 in words is "thirteen billion, two hundred ten thousand, three hundred nine".
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